I need steps broken down so that I can understand how to solve these kinds of problems.
Answers (3)
Here's another problem, but similar :
x2+7x+12=0
x^(2)+7x+12=0
For a polynomial of the form x^(2)+bx+c, find two factors of c (12) that add up to b (7). In this problem 4*3=12 and 4+3=7, so insert 4 as the right hand term of one factor and 3 as the right-hand term of the other factor.
(x+4)(x+3)=0
Set each of the factors of the left-hand side of the equation equal to 0.
x+4=0_x+3=0
Since 4 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 4 from both sides.
x=-4_x+3=0
Set each of the factors of the left-hand side of the equation equal to 0.
x=-4_x+3=0
Since 3 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 3 from both sides.
x=-4_x=-3
The complete solution is the set of the individual solutions.
x=-4,-3
I tried my best! Sorry if it didn't help or make any sense.
The only way I can do this:
x^2 + x - 3/4 = 0
First I draw this out:
(x + _)(x - _)=0 Because that is the only way to get a negative third value and a positive first. ALso the (x+_) must be larger than the (x - _) to produce a positive second value.
(x + 1.5)(x - .5) = 0 Because this is the only values that multiplied equal .75 and added equal 1
Thus (x = -1.5 and +.5) Based on the fact that either will make the left equal to the right (0=0)
