Gamma ray radiation falls in the wavelength region of 1.00E-16 to 1.00E-11 meters. What is the?

Your problem can be solved by using the formula known as the Planck-Einstein relation:

E=h*ν;
"E" is the energy of the photon; in J (Joules)
"h" is the Planck constant: 6.62606957*10^(−34) J*s
"v" is the frequency of the wave ; in 1/s or s^(-1)

Since you've been given the wavelength(called λ), and the speed of ligt (called c) is the product of the λ and v (frequency), that is λ*v=c, Planck-Einstein can be formed as:

E=h*c/λ (use this formula!)
"/" means divide, i case you're not use to my script.
c= 300.000.000 m/s
λ= 1E-16 m

E = 6.62606957*10^(−34) * 300.000.000 / 10e-16 J*s*m/s/m = 1.98782E-09 J

And here you have the photon energy.