2 3 n-1 n-1 n n

SERIES FOR LOG (1+x) is derived from 1/(1+u)=1-u+u-u+...(-1) u +(-1) u/(1+u

by performing the long division of 1 / ( 1+u )

How is it done?

Thank You very much Peter

# How to perform / do a long division in mathematics for 1 / (1+u)?

- Posted:
- 3+ months ago by peterj
- Topics:
- log, performing, series, perform, mathematics, division

Details:

Thank You for replying to my question - Long Division for 1 / ( 1 + u )

HSC Mathematics Form 6 Level 1 Coroneos & Lynch 1967 SERIES FOR LOG(1+x)

1/(1+u)=1-u+u^2-u^3+...(-1)^n-1 u^n-1 + (-1)^n u^n / ( 1+u )

How is it done ? Thank You very much. Kind regards Peter peterj