Limit x tending to 0 d/dx square root of (1-cos2x)?

Responses (2)

standard formula is d/dx(cosax)= - asin(ax)

rule states dat d/dx(constant)=0
d/dx(u+v)=du/dx +dv/dx
in the same way

d/dx(1-cos2x)=2sin2x
here minus X minus bcoms +....................................
clear now

Votes: +1 / -0

it is square root na so ans is

d/dx sqre rot of (1-cos2x) = 1/ 2 Xsquare root of (1- cos2x) X 2sin2x

here 2 & 2 get cancle

answer will b
1/ (sqre root of 1-cos2x) X sin2x


bcoz d/dx(sqre rot of x) = 1/ 2 X sqre root of x

Votes: +1 / -0

Thanks Mohini,, but u didnt apply the limit...