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... ∀x∃y(2x-y=0)b) ∃y∀x(2x-y=0)c) ∀x∃y(x-2y=0)d) (∀x)(x<10)→(∀y)(y<x→y<9)e) (∃y)(∃z)(y+z=100)f) (∀x)(∃y)(y>x^∃z.y+z=

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