the width of a rectangle is 3 less than its length. if the length is multiplied by 2 and the width is increased by 4, the perimeter is now 50. What's the new dimensions?
The width of a rectangle is 3 less than its length. if the length is multiplied by 2 and the width?
- Posted:
- 3+ months ago by katherine...
- Topics:
- perimeter, math, algebra, length
Details:
Answers (2)
"The width of a rectangle is 3 less than its length."
x = y - 3
P = 2(x + y)
" if the length is multiplied by 2 and the width is increased by 4, the perimeter is now 50."
P = 2(x + 4 + 2y) = 50 Now substitute #1 for x.
P = 2(y - 3 + 4 + 2y) = 50
2y - 6 + 8 + 4y = 50
6y = 48
y = 8
x = 5
