A father is jewelry maker and he has 10 sons. He gives each son 20g of gold and tells them to make 10 gold rings each. One son cheats on his rings; he uses only 10g of gold to make 10 rings and pockets the the other 10g. Now the father has collected all 10 rings from each son and wants to see if the one son cheated. He can only use and read the scale ONCE. How does the father figure out who cheated?
I need an answer to this Riddle ASAP?
- Posted:
- 3+ months ago by batmanwom...
- Topics:
- gold, father, ring, jewelry, answer, riddle, son, brain teasers
Details:
Answers (1)
Easy. Each ring is supposed to weigh 2 grams, right?
Put the following on the scale: One ring from son #1, 2 rings from son #2, three rings from son #3, etc. ending in 10 rings from son #10. This is a total of 55 rings. If none of the sons cheated, it should weigh 110 grams. If it's 1 gram short, son #1 cheated. 2 grams short, son #2, and so on. Get it?